Brooks Brown's teammates

Brooks Brown has had 69 MLB teammates in 2 seasons with the Colorado Rockies. He spent the most seasons beside Nolan Arenado (2), Troy Tulowitzki (2), and Charlie Blackmon (2). Every season since 1876 is on file.

With the Colorado Rockies2014–2015 · 69 teammates

TeammateSeasonsTogether
Nolan Arenado8× All-Star22014–2015
Troy Tulowitzki5× All-Star22014–2015
Charlie Blackmon4× All-Star22014–2015
Justin Morneau4× All-Star22014–2015
Carlos Gonzalez3× All-Star22014–2015
DJ LeMahieu3× All-Star22014–2015
Corey Dickerson1× All-Star22014–2015
Adam Ottavino22014–2015
Ben Paulsen22014–2015
Boone Logan22014–2015
Brandon Barnes22014–2015
Chad Bettis22014–2015
Christian Bergman22014–2015
Christian Friedrich22014–2015
Cristhian Adames22014–2015
Drew Stubbs22014–2015
Eddie Butler22014–2015
Jordan Lyles22014–2015
Jorge De La Rosa22014–2015
Kyle Parker22014–2015
LaTroy Hawkins22014–2015
Matt McBride22014–2015
Michael McKenry22014–2015
Rafael Ynoa22014–2015
Rex Brothers22014–2015
Tommy Kahnle22014–2015
Tyler Matzek22014–2015
Wilin Rosario22014–2015
Yohan Flande22014–2015
Jose Reyes4× All-Star12015
Michael Cuddyer2× All-Star12014
Jair Jurrjens1× All-Star12014
Aaron Laffey12015
Brett Anderson12014
Charlie Culberson12014
Chris Martin12014
Chris Rusin12015
Daniel Descalso12015
David Hale12015
Dustin Garneau12015
Franklin Morales12014
Gonzalez Germen12015
Jackson Williams12014
Jairo Díaz12015
Jason Gurka12015
Jason Pridie12014
Jhoulys Chacin12014
John Axford12015
Jon Gray12015
Jordan Patrick Pacheco12014
Jorge Rondon12015
Josh Rutledge12014
Juan Nicasio12014
Justin Miller12015
Ken Roberts12015
Kyle Kendrick12015
Matt Belisle12014
Miguel Castro12015
Nick Hundley12015
Nick Masset12014
Pedro Hernandez12014
Rafael Betancourt12015
Rob Scahill12014
Ryan Wheeler12014
Scott Oberg12015
Simon Castro12015
Tom Murphy12015
Tyler Chatwood12014
Wilton Lopez12014

A teammate is anyone on the same club in the same season, whether or not their games overlapped; a player traded mid-season counts with both clubs. Most seasons together first.